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-2b^2-15b+17=0
a = -2; b = -15; c = +17;
Δ = b2-4ac
Δ = -152-4·(-2)·17
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-19}{2*-2}=\frac{-4}{-4} =1 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+19}{2*-2}=\frac{34}{-4} =-8+1/2 $
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